2 sides of an equilateral triangle have lenghts of 3x+1 and -2x+26. could 21- x or 3x-4 be the lenght of the 3rd side?
a. both 21-x and 3x-4
b. 21-x only
c. neither 21-x nor 3x-4
d. 3x-4 only
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ganeshie8 (ganeshie8):
hint : in equilateral triangle, all sides are equal
ganeshie8 (ganeshie8):
they gave u 2 sides.... set them equal, and solve x first
OpenStudy (anonymous):
3x+1+-2x+26??
OpenStudy (anonymous):
@ganeshie8
ganeshie8 (ganeshie8):
yu need to set them equal, cuz sides are equal
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ganeshie8 (ganeshie8):
like this :
3x+1 = -2x+26
ganeshie8 (ganeshie8):
solve x now
OpenStudy (anonymous):
oh okay, 3x+1=-2x+26
+x +x
OpenStudy (anonymous):
im sorry im a little slow
OpenStudy (anonymous):
x=5
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ganeshie8 (ganeshie8):
it's :)
ganeshie8 (ganeshie8):
3x+1=-2x+26
ganeshie8 (ganeshie8):
add 2x both sides
ganeshie8 (ganeshie8):
3x+1=-2x+26
+2x +2x
ganeshie8 (ganeshie8):
5x + 1 = 26
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ganeshie8 (ganeshie8):
subtract 1
OpenStudy (anonymous):
substitute the value of x, =16 both sides :)
OpenStudy (anonymous):
5x+1=-4x+26
-1 -1
ganeshie8 (ganeshie8):
yes, keep going
ganeshie8 (ganeshie8):
hey no wait
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ganeshie8 (ganeshie8):
we got this right,
5x + 1 = 26
ganeshie8 (ganeshie8):
subtract 1
ganeshie8 (ganeshie8):
5x + 1 = 26
-1 -1
5x = 25
OpenStudy (anonymous):
-2x+26=3x+1
-2x-3x=1-26
-5x=-25
x=5
then substitute the value of x
OpenStudy (anonymous):
side 1
3x+1= 3(5)+1 =16
side 2
-2x+26= -2(5)+26 =-10+26 =16
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OpenStudy (anonymous):
so its a
OpenStudy (anonymous):
@engr04
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@terenzreignz
ganeshie8 (ganeshie8):
read the q once,
could 21- x or 3x-4 be the lenght of the 3rd side?
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OpenStudy (anonymous):
no?
OpenStudy (anonymous):
it's b
ganeshie8 (ganeshie8):
you got x = 5
OpenStudy (anonymous):
21-x
21-5=16 correct
but, 3x-4
3(5)-4=11 incorrect so it's only 21-x
the answer is b :)