Question

Help with C programming:

here is my code, and I can't show the final result!

Answer 1

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
#include<string.h>
typedef struct{char names[30];
int age;
char position[30];
char sex;} data;
void age(data *emp; int n;);
void sex(data *emp; int n;);
void name(data *emp; int n;);
void pos(data *emp; int n;);
void show(data *emp; int n;);
data *emp=0;
int n=0,i;
char ch;

void input(data *emp);
int main(){


printf("Input employees' information here:\n");
again:
printf("\nEmployee[%d]:\n",n+1);
emp=(data*)realloc(emp,(n+1)*sizeof(data));
if(emp==0) return 0;
printf("%10s:","Name"); scanf("%30[^\n]",(emp+n)->names); fflush(stdin);
printf("%10s:","age"); scanf("%d",&((emp+n)->age)); fflush(stdin);
printf("%10s:","Position"); scanf("%30[^\n]",(emp+n)->position); fflush(stdin);
printf("%10s:","Sex"); scanf("%c",&((emp+n)->sex)); fflush(stdin);
n++;
printf("\nMore employee? (ESC to stop): ");
if(getch()!=27) goto again;
printf("Here are all of your employees' information:");
for(i=0;i<n;i++){
printf("\n[%d]",i+1);
printf("\t%s",emp[i].names);
printf("\t%d",emp[i].age);
printf("\t%s",emp[i].position);
printf("\t%c",emp[i].sex);}
printf("\nWhat do you want data to be sorted by?\n");
printf("1/ names\n2/ age\n3/ position\n4/ sex\n");
printf("\nYour choice: ");
ch=getche();
switch(ch){
case 1 : name(emp, n); show(emp, n); break;
case 2 : age(emp, n); show(emp, n); break;
case 3 : pos(emp, n); show(emp, n); break;
case 4 : sex(emp, n); show(emp, n); break;}
return 0;
}

void name(data *emp; int n;){
int i,j;
char temp[30];
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++)
if(strcmp(emp[i].names,emp[j].names)>0) {strcpy(temp,emp[i].names);
strcpy(emp[i].names,emp[j].names);
strcpy(emp[j].names,temp);}

}

void pos(data *emp; int n;){
int i,j;
char temp[30];
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++)
if(strcmp(emp[i].position,emp[j].position)>0) {strcpy(temp,emp[i].position);
strcpy(emp[i].position,emp[j].position);
strcpy(emp[j].position,temp);}

}

void age(data *emp; int n;){
int i,j, temp;
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++){
if(emp[i].age>emp[j].age) {temp=emp[i].age;
emp[i].age=emp[j].age;
emp[j].age=temp;}
}

}

void sex(data *emp; int n;){
int i,j;
char temp;
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++){
if(emp[i].sex!=emp[j].sex) {temp=emp[i].sex;
emp[i].sex=emp[j].sex;
emp[j].sex=temp;}
}

}

void show(data *emp; int n;){
int i;
printf("\nHere are sorted lists:\n\n");
for(i=0;i<n;i++){
printf("\n[%d]",i+1);
printf("\t%s",emp[i].names);
printf("\t%d",emp[i].age);
printf("\t%s",emp[i].position);
printf("\t%c",emp[i].sex);}

}

Answer 2

Can you use a code paste site, like pastebin, github's gist, or one of the others? If people copy and paste from OpenStudy, it removes all newline markers and makes a mess of code.

Answer 3

One problem that I see here, unless it is a formatting anomaly, is that your name, pos, age, and sex functions are missing braces.

Answer 4

You also separate your arguments being passed to your functions with a ';'(semicolon) instead of a ','(comma)

Answer 5

Did this program compile for you?

Answer 6

I have changed the ; into commas, but it still didn't show the final result

Answer 7

And I compiled this in CodeBlock, and it worked also.

Answer 8

http://pastebin.com/uXJ8JcZ3

Answer 9

thanks. I have found the solution. :)

Answer 10

Glad to hear it.