Question

Solve for x by completing the square: 4x2 + 6x - 6 = 0
A. (-3+√33)/4, (-3-√33)/4
B. (3+√33)/4, (3-√33)/4
C. 3, -2
D. 1, 6

Answer 1

\(\large 4x^{2}+6x-6=0\)
\(\large 2(2x^{2}+3-3=0\)

try use this formula \(\large x = (-b ± √(b² - 4ac))/(2a)\)