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identify the maxiumum or minimum value of the function f(x)= (x+3)^2-11
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Find f´(x) and set f´(x)=0
A) (-11,3) maximum B) (-3,-11) maximum C) (3,-11) minimum D) (-3,-11) minimum
\[f(x)=(x+3)^2-11=x^2+6x-2\] what is f´(x)?
3,-11?
No... \[f'(x)=2x+6\]
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\[2x+6=0\] Find x
x=3
-3*
Yes... Then find f(-3)
-11
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Yes.. :)
idk if its a maximum or minimum
You have to se its a parable.
The function for a parable is f(x)=ax^2+bx+c
|dw:1372270977184:dw|
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