Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Could someone help me find XS in this problem? (pic below)

OpenStudy (anonymous):

OpenStudy (anonymous):

I did the first step. I think its wrong tho.

ganeshie8 (ganeshie8):

its correct !!

ganeshie8 (ganeshie8):

next, solve b

OpenStudy (anonymous):

solve B huh? ...Uhm.. How would one do that? o:

OpenStudy (anonymous):

Thats where im stuck.

ganeshie8 (ganeshie8):

\(\large 3b-1 = b + 5\)

ganeshie8 (ganeshie8):

subtract \(b\)

OpenStudy (anonymous):

from? o:

ganeshie8 (ganeshie8):

\(\large 3b-1 = b + 5\) -b -b

OpenStudy (anonymous):

Ohh.. 3-1=5.

OpenStudy (anonymous):

then add 1 to each side?

ganeshie8 (ganeshie8):

dont forget b

ganeshie8 (ganeshie8):

\(\large 2b-1 = 5\)

ganeshie8 (ganeshie8):

yes, add 1 both sides

OpenStudy (anonymous):

2b=6

OpenStudy (anonymous):

b=3

ganeshie8 (ganeshie8):

b=3, but u need to find XS

OpenStudy (anonymous):

yes??

OpenStudy (anonymous):

so 3 +3 ??

ganeshie8 (ganeshie8):

look at the pic

OpenStudy (anonymous):

i did.

ganeshie8 (ganeshie8):

\(XS = 3b-1 + b + 5 \)

OpenStudy (anonymous):

so.. 3 is my answer??

ganeshie8 (ganeshie8):

\(XS = 4b + 4 \)

OpenStudy (anonymous):

i keep getting it wrong. :/

ganeshie8 (ganeshie8):

\(XS = 4b + 4 \) plugin \(b=3\)

OpenStudy (anonymous):

16

ganeshie8 (ganeshie8):

\(XS = 4b + 4 \) = 4(3) + 4

ganeshie8 (ganeshie8):

yes, XS = 16

OpenStudy (anonymous):

Thanks! :D Do you think you could check one more problem for me? o:

ganeshie8 (ganeshie8):

sure :)

OpenStudy (anonymous):

Ok. thanks! Its super easy.. but i think theire trying to trick me. o:

OpenStudy (anonymous):

I got 26 as my answer btw. (:

ganeshie8 (ganeshie8):

and thats the right answer !!

OpenStudy (anonymous):

thanks!!! :D

ganeshie8 (ganeshie8):

you're wlcme :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!