The length of a rectangle is 2 more than 3 times the width. If the perimeter is 100, find the length and width of the rectangle.

If l = length and w = width, which of the following systems could be used to solve the problem?

l = 3w + 2 and 2l + 2w = 100
l = 2w + 3 and 2l + 2w = 100
l + 2 = 3w and 2l + 2w = 100

Question

The length of a rectangle is 2 more than 3 times the width. If the perimeter is 100, find the length and width of the rectangle.



If l = length and w = width, which of the following systems could be used to solve the problem?

l = 3w + 2 and 2l + 2w = 100
l = 2w + 3 and 2l + 2w = 100
l + 2 = 3w and 2l + 2w = 100

anonymous · Answer

L=2+3W
2L + 2W = 100

the only thing you have to think about is the equation of the perimeter

anonymous · Answer

since it's a rectangle, it's 2W +2L = P... in this case P was 100