Can someone proofread my work. I have seen the answer to my question online and it differs by a negative sign. Just wondering If I was on the right track
Hello there! I am reviewing your question. :)
Thanks. I skipped alot of steps but you should be able to follow what I did
Yeah, I can. Those steps weren't completely necessary anyway. :) You have lovely handwriting by the way!
Thanks
Your computation is correct. Good work! :)
The answer I have seen is \( C_{k+2}=\large \frac{k-2}{k+2}C_{k+1} - \frac{C_k}{k+2}\)
hmm.... I feel this is a computational error. But let me see... @ParthKohli ?
So I'm gonna teach Swissgirl now? Impossible :L
yaaaaaaaaaaaa can you review my work?
Nope.
ahaaaaaaaaaaaa
I can't, because I can't
@Zarkon Can you please check my work?
@amistre64 Can you please check my work?
It looks ok to me. if your answer does not match the book's then there is probably a typo lurking somewheres...
Ya it looks ok to me too. I think I will just stick to my answer. Thanks sooooooo much :)
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