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Mathematics 16 Online
OpenStudy (anonymous):

what are the vertical asymptotes of the function f(x) = 5x+1/x^2+x-6

OpenStudy (cwrw238):

vertical asymptotes occur where the denominator = zero

OpenStudy (cwrw238):

so x^2 + x - 6 = 0 solve for x

OpenStudy (anonymous):

Yeah, I already got the answer x = 2 and x= - 3

OpenStudy (cwrw238):

right - those are the asymptotes x = 2 and x = -3

OpenStudy (anonymous):

thank you!

OpenStudy (cwrw238):

yw

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