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Mathematics 7 Online
OpenStudy (anonymous):

There are 4 colas,1 Ginger ale,7 rootbeers, and 6 cherry colas what are the odds in favor of choosing rootbeer

OpenStudy (anonymous):

number of root beers to number of not root beers

OpenStudy (anonymous):

number of root beers to all drinks so it is 7/18

OpenStudy (anonymous):

no, actually that is the probability, not the odds

OpenStudy (anonymous):

they are not the same, although you can get one from the other

OpenStudy (anonymous):

7/18 is not correct

OpenStudy (anonymous):

yes, i know it is not correct

OpenStudy (anonymous):

\(\frac{7}{18}\) is the PROBABILITY of getting a root beer

OpenStudy (anonymous):

it is 7/12

OpenStudy (anonymous):

no that is not correct either

OpenStudy (anonymous):

are the odds in percentage or decimal for

OpenStudy (anonymous):

at the risk of repeating myself number of root beers to number of not root beers

OpenStudy (anonymous):

7/12 nope

OpenStudy (anonymous):

lorda mercy how many root beers?

OpenStudy (anonymous):

but that is what I did 7/11

OpenStudy (anonymous):

there are 7 root beers and the other drinks added is 11 so the answer is 7/11 right

OpenStudy (anonymous):

yes, that is right

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