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Mathematics 13 Online
OpenStudy (anonymous):

what is the solution set of x^2+5x-5=0

OpenStudy (amistre64):

well, there are a few methods that can be approached, are you familiar with the quadratic formula? or maybe, completing the square?

OpenStudy (anonymous):

Yes i am familier with it.

OpenStudy (amistre64):

then this would be a prime opportunity to use it :)

OpenStudy (amistre64):

given a quadratic equation of the form:\[ax^2+bx+c\] the solution set can be determined using the quadratic formula \[x=\frac{1}{2a}(-b\pm\sqrt{b^2-4ac})\]

OpenStudy (anonymous):

thanks :)

OpenStudy (amistre64):

good luck ;)

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