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what is the solution set of x^2+5x-5=0
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well, there are a few methods that can be approached, are you familiar with the quadratic formula? or maybe, completing the square?
Yes i am familier with it.
then this would be a prime opportunity to use it :)
given a quadratic equation of the form:\[ax^2+bx+c\] the solution set can be determined using the quadratic formula \[x=\frac{1}{2a}(-b\pm\sqrt{b^2-4ac})\]
thanks :)
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good luck ;)
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