What is the solution of the system? Use substitution.

x = –2y + 10
–6y = 6x – 6
z = –3x + 10y

A. x = 9, y = –8, z = 114

B. x = –8, y = 9, z = 114

C. x = –8, y = 114, z = 9

D. x = 114, y = 9, z = –8

Question

What is the solution of the system? Use substitution.

x = –2y + 10 
–6y = 6x – 6 
z = –3x + 10y

A. x = 9, y = –8, z = 114	

B. x = –8, y = 9, z = 114	

C. x = –8, y = 114, z = 9	

D. x = 114, y = 9, z = –8

dls · Answer

x = –2y + 10 ..(i)
–6y = 6x – 6...(ii)
 z = –3x + 10y... (iii)

-6y=6(-2y+10)-6....(iv)
Solve for y.

Then substitute in (i) to solve for x.

Use y and x to solve for z in (iii)

anonymous · Answer

hope this helps :) http://openstudy.com/study#/updates/4f9309afe4b000ae9ec9d0b4

anonymous · Answer

it did thx

anonymous · Answer

No problem :)