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Mathematics
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Reduce the following fraction: -32ABC/64AsqrdBCcubed a)-1/2ACsqrd b)-16AC/32ACsqrd c)1ACsqrd/2 d)-32/64ACsqrd
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look at the problem in parts \[\frac{-32}{64} = \] \[\frac{A}{A^2} = \] \[\frac{B}{B} = \] \[\frac{C}{C^3}\] the solution is the product of the 4 answers above
please help, im dumb lol
whats 32/64 =
is tht the answer?
\[\frac{-32}{64} = \frac{-1}{2}\] \[\frac{A}{A^2} = \frac{1}{A}\] \[\frac{B}{B} = 1\] \[\frac{C}{C^3} = \frac{1}{C^2}\] so your answer is \[\frac{-1}{2} \times \frac{1}{A} \times \frac{1}{C^2} \times 1\] just write it correctly
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kay thanks
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