Question

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With the restriction x ≠ 2, which of the following is the simplified form of 3 x plus 4 over x minus 2 minus the fraction x minus 8 over x minus 2 ?

1

4 times the quantity x plus 3 end quantity over x minus 2

x – 2

2 times the quantity x plus 6 end quantity over x minus 2

Answer 1

\[\begin{align*}\frac{3x+4}{x-2}-\frac{x-8}{x-2}&=\frac{3x+4-(x-8)}{x-2}\\
&=\frac{2x+12}{x-2}
\end{align*}\]
How else can you write this?

Answer 2

I'm not sure?

Answer 3

@dreamer05 he's saying that you could factor the numerator by 2, making it\[\frac{ 2(x+6) }{ x-2 }\]

making the answer

2 times the quantity x plus 6 end quantity over x minus 2