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Mathematics 21 Online
OpenStudy (mathisfun13):

Find the sum of this infinite geometric series

OpenStudy (mathisfun13):

OpenStudy (callisto):

What is the common ratio?

OpenStudy (mathisfun13):

uhmm 8/3?

OpenStudy (zzr0ck3r):

what is 4/6=(8/3)/4=?

OpenStudy (zzr0ck3r):

divide the second term by the first to get the common ratio in a geometric series

OpenStudy (zzr0ck3r):

so what is the common ratio?

OpenStudy (mathisfun13):

32/3?

OpenStudy (zzr0ck3r):

what is the first term?

OpenStudy (mathisfun13):

6....

OpenStudy (zzr0ck3r):

what is the second term?

OpenStudy (mathisfun13):

4

OpenStudy (zzr0ck3r):

is 4/6=32/3?

OpenStudy (mathisfun13):

noooo its .6 repeating

OpenStudy (zzr0ck3r):

ok so the ratio is 4/6=2/3 so the answer is \[\frac{first.term}{1-ratio}\]

OpenStudy (mathisfun13):

15

OpenStudy (zzr0ck3r):

\[\frac{first.term}{1-.6666666...}=\frac{4}{1-\frac{2}{3}}\]

OpenStudy (mathisfun13):

u said the first term was 6

OpenStudy (zzr0ck3r):

sorry 6

OpenStudy (mathisfun13):

it be 12 than

OpenStudy (mathisfun13):

lol so its 15

OpenStudy (zzr0ck3r):

\[\frac{6}{1-\frac{2}{3}}=\frac{6}{\frac{1}{3}}=6*3\]

OpenStudy (mathisfun13):

oooh 18

OpenStudy (zzr0ck3r):

correct

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