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Find the sum of this infinite geometric series
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What is the common ratio?
uhmm 8/3?
what is 4/6=(8/3)/4=?
divide the second term by the first to get the common ratio in a geometric series
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so what is the common ratio?
32/3?
what is the first term?
6....
what is the second term?
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4
is 4/6=32/3?
noooo its .6 repeating
ok so the ratio is 4/6=2/3 so the answer is \[\frac{first.term}{1-ratio}\]
15
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\[\frac{first.term}{1-.6666666...}=\frac{4}{1-\frac{2}{3}}\]
u said the first term was 6
sorry 6
it be 12 than
lol so its 15
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\[\frac{6}{1-\frac{2}{3}}=\frac{6}{\frac{1}{3}}=6*3\]
oooh 18
correct
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