Question

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Which of the following is the simplified form of 4 times x cubed over 9 times y to the fourth power divided by 8 times x to the fifth power over 3 times y squared ?

6x2y2

6 over x squared times y squared

1 over 6 times x squared times y squared

x squared times y squared over 6

Answer 1

so you are looking at

\[\frac{\frac{4x^3}{9y^4}}{\frac{8x^5}{3y^2}}\]

the rule is flip the denominator and multiply so you are looking at

\[\frac{4x^3}{9y^4} \times \frac{3y^2}{8x^5}\]

cancel the common factors, whats left is the answer.

Answer 2

None of them are common.

Answer 3

really well lets look at it bits

\[\frac{12x^3y^2}{72x^5y^4} = \frac{12}{72} \times \frac{x^3}{x^5} \times \frac{y^2}{y^4}\]

can you simplify anything the the expanded form above.

Answer 4

>.<

Answer 5

what does 12/72 simplify to...?

Answer 6

6?

Answer 7

or its .16

Answer 8

not quite.... 12/72 = 1/6

divide the numerator and denominator by 12

and you need a fraction answer...

next...

\[\frac{x^3}{x^5} = \frac{x \times x \times x}{x \times x \times x \times x \times x}\]


what do you think this will simplify to...?