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if log2 = 0.3010 and log3 = 0.4771; then log300 - log8 = 1.5741 .... true or false? why?
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but log5 isnt given...ur only supposd to use log2 and log3
log(300)=log(3*100)=log(3*10^2)=log3 + 2log10
Sorry I was supposed to stop there
=log3+2*1=2+log3
log8=log2^3=3log2
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So just find: 2+log3-3log2
And that does in fact equal 1.5741
log300 - log8 \[\log(3\times100)-\log2^{3}=\log3+2\log10-3\log2=\log3+2\times1-3\log2\] =0.4771 +2-3*0.3010 =2.4771 -0.9030=1.5741 Thus the answer is true
thank u :)
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