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slope of the line (-11,6) (12,-3)
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\[\huge (\frac{ 1 }{ 2 },\frac{ 3 }{ 2 })\]
slope =\[\frac{ y2-y1 }{ x2-x1 }\]
Slope will be 9/23
yes!!
sorry i found out the midpoints!
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\[\huge- \frac{ 9 }{ 23 }\]
slope(m) = (y2 - y1)/(x2 - x1) set 1 (-11,6) set 2 (12,-3) m = (-3 -6) / (12 - (-11) m = - 9 / 23 kapil is correct.....slope is - 9/23
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