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Verify the identity. 4 csc 2x = 2 csc^2x tan x
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sin ( 2x) = 2 sin (x) cos (x)
csc (x) = 1/ sin (x)
Where did the 4 go?
it turned into a 2
\[4 \csc(2x) = \frac{4}{\sin(2x)}\]
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Oh okay
do you know how to solve it now or do i need to walk you through it?
I understand now. It's a double angle identity
ok
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