Question

Please factor
a^2 – 5a – 20

Answer 1

a=15

Answer 2

Explain please?

Answer 3

Trying

Answer 4

ok

Answer 5

Hard

Answer 6

Use the quadratic formula \[\large x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]\[\large a = 1 \ ,\ b=-5 \ , \ c=-20\]

Answer 7

^cheats

Answer 8

if you get a=15 try solving the question again

Answer 9

How am i cheating?

Answer 10

I though you cant use quadratic equation

Answer 11

What's stopping you?

Answer 12

Nothing just my mom told me not too

Answer 13

FYI its algebra 1... ^confused me...!

Answer 14

I honestly think you only solve this question with the quadratic equation

Answer 15

are you sure?

Answer 16

Not sure but imma trying

Answer 17

no he is wrong you can i got my answer like that

Answer 18

\[\large x = \frac{-(-5) \pm \sqrt{(-5)^2 -4(1)(-20)}}{2(1)}\]\[\large \frac{5\pm \sqrt{25+80}}{2}\]\[\large \frac{5 \pm \sqrt{105}}{2}\]

Answer 19

jhanney using cheats again

Answer 20

So its either 7.62 or -2.62

Answer 21

no pak asfand is wrong again

Answer 22

\[\large a^2 -5a -20\]\[\large (a^2-5a)-20\]complete the square. \[\large (a^2-5a+\frac{25}{4})-\frac{25}{4}-20\]\[\large (a-\frac52)^2 -\frac{105}{4}\] Now to solve for a... put -105/4 on the other side.

Answer 23

There are several ways to solve this.....