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Algebra
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OpenStudy (anonymous):
(2-i)+(3i+2) help solve please
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terenzreignz (terenzreignz):
Complex numbers? The constant i behaves like most any other variable. The only difference is that \(i^2\) is something special, in that it's equal to -1.
OpenStudy (anonymous):
(2-i)+(3i+2) =2-i + 3i+2= 4-2i
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