Solve 3x^ 2 + 11x + 6 = 0

Question

ashleyisakitty · Answer

Is that 3x^2?

anonymous · Answer

Solve 3x^2 + 11x + 6 = 0
sorry wrote it wrong

shamim · Answer

$$x=\frac{ -11\pm \sqrt{11^{2}-4 \times 6 \times 3}}{ 2 \times 3 }$$

shamim · Answer

did u get it

anonymous · Answer

$$3x^2+11x+6=0$$

U gotta multiply 3x² and 6, mentally . its 18x²
 -Now u gotta find two numbers that are factors of 18x² yet they add up to 11x.
-11x is the middle term btw

Those 2 numbers are 9x and 2x... ((EX: 9x*2x=18x²    9x+2x=11x))
- Now fill those 2 numbers in for 11x

3x²+9x+2x+6=0 (undistribute)
3x(x+3)+2(x+3)=0 (grouping)
(3x+2)(x+3)=0       FINAL ANSWER= x= -2/3, x=-3

anonymous · Answer

the explanation for the last part,  is:

(3x+2)(x+3)=0 

3x+2=0                       x+3=0
     -2  -2                         -3 -3

3x=-2                     x=-3
/3     /3

x=-2/3