Question

csc2 θ = 8 cot θ + 10

Answer 1

can anyone please help

Answer 2

can you show me the steps to how to solve this?

Answer 3

you should note that csc^2 x = 1 + cot^2 x

after you re arrange some terms , you'll see a quadratic equation formed in cot x

Answer 4

yes, is that \(\csc^2 \theta =8 \cot \theta+10\) ??
and you need to solve for thetha ?
any interval given ?

Answer 5

\[\csc ^{2}\theta=8\cot \theta+10\]
\[1+\cot ^{2}\theta=8\cot \theta+10\]
\[\cot ^{2}\theta-8\cot \theta-9=0\]
1*-9=-9
9-1=8
\[\cot ^{2}\theta-\left( 9-1 \right)\cot \theta-9=0\]
now you can solve.