Question

http://prntscr.com/1clobx

Help!

Answer 1

expand and compare coefficients left side and right side

Answer 2

2w^2-aw+6w-3a=bw^2-w+3c
2w^2+w(-a+6)-3a

Answer 3

-2 ans hai

Answer 4

2w^2-aw+6w-3a=bw^2-w+3c
2w^2-bw^2-aw+6w=w-3a+3c
w^2(2-b)-w(a+5)-3(a+c)
i am getting this after expansion??

Answer 5

keep left side and right side separately

Answer 6

2w^2-aw+6w-3a=bw^2-w+3c

Answer 7

seperately karooo

Answer 8

write left side as a quadratic in w

Answer 9

ok wait!

Answer 10

ok ok i got this !
thanks guys! :)

Answer 11

np

Answer 12

solution post karo :p

Answer 13

agaya na woi kafi hai :)

Answer 14

aray mujhay dekhna tha mainay jo solve kia tha its all jumbled up :p

Answer 15

2w^2-wa+6w-3a=bw^2-w+3c
2w^2-w(a-6)-3a=bw^2-w+3c
now compare the terms
b=2, a=6+1, c=a
ab agaya?

Answer 16

everything correct, except one thing

Answer 17

im getting c= -a

Answer 18

yup :p

Answer 19

@ganeshie8 oh yeah my bad! :P

Answer 20

:) if we get c=a, then we wont be able to find a-b+c

Answer 21

cuz, c sticks in the expression

Answer 22

for clarity. herez the full work :-

2w^2 + 6w - wa - 3a = bw^2 -w + 3c

2w^2 + (6-a)w - 3a = bw^2 - w + 3c

compare coefficients of w^2, w and constant terms
b = 2

6-a = -1
a = 7

3c = -3a
c = -a

a-b+c = a-b-a
= -b
= -2