Question

Where does the graph of y = 6x^2 − 11x − 10 cross the x-axis?

(−2/3, 0) and (5/2, 0)

(2/3, 0) and (−5/2, 0)

(−5/6, 0) and (2, 0)

(5/6, 0) and (−2, 0)

Answer 1

\[x=(-b+or-\sqrt{b^2-4ac})/2a\]

Answer 2

-b= 11
b^2= 121
a=6
c=-10
2a=12

Answer 3

\[x= (11 (plus or Minus)\sqrt{121- (4)(6)(-10)})\div12\]

Answer 4

\[x= (11+-\sqrt{121+240})\div12\]

Answer 5

\[x= (11+-\sqrt{361})\div12\]

Answer 6

(11+19)/12 = 5/2 -----> x= 5/2

(11-19)/12 = -2/3 -----> x=-2/3