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Mathematics 14 Online
OpenStudy (anonymous):

Find all solutions of the equation 2sin^2x=2−cosx in the interval [0,2π)

OpenStudy (anonymous):

Solutions are x=0,pi/2,pi,3pi/2

OpenStudy (anonymous):

I found these by graphing the equation here: http://www.wolframalpha.com/input/?i=sin%5E2x-1%2B%281%2F2%29cosx%3D0

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