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The Disappearance of Sqrt6: How did it Happen?
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I am so curious as to how it happened? please help...
It vannished into \(\bar{C}\)
\(\overline{C} = C + 3\ln \sqrt{6}\)
thanks.. can i do that to other similar equations? so that i could get rid of the denominator inside the ln...
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yes as long as we have constant in bottom... we can do that...
ln ( a/b) = ln a - ln b, therefore, the second term is 3ln sqrt(6) , + C =Cbar
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