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Calculus1 18 Online
OpenStudy (anonymous):

critical numbers of f(x)=x-cosx for 0

OpenStudy (anonymous):

I think its pi/2?

OpenStudy (anonymous):

f'(x)=1+sinx for critical point, 1+sinx=0 => sinx=-1. =>x=3pi/2, since 0<x<2pi.

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