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What is the equation of the line that passes through the point (4, 1) and has a slope of 5? A. y = 5x - 3 B. y = 5x - 1 C. y = 5x + 3 D. y = 5x - 19
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if you use \[y - y_{1}=m(x-x{1})\] and plug in your slope and x and y and solve for y you will get a \[y = mx + b\] finsh and you will have your answer
Or use y=mx+b where m is slope, and our slope is 5 and b is y intercept so plug in what we know y=5x+b and the like has to go through the point (4,1) so plug in 4 for the x and 1 for y and solve for b 1=5(4)+b b=-19 final answer: y=5x=19
^ yep thank you condawg :)
=) np
Thank u that helped me to understand it better
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