Question

Can anyone explain to me graph of
sin^-1 (sinx)
from x = 0 to 5pi/2 ?

Answer 1

I am getting confused in the intervals ahead of (0,pi/2)

Answer 2

sinx range doesnt go beyong \(\pm 1\)

Answer 3

*beyond

Answer 4

so the peak value of sin^-1 (sinx) would be sin^-1 (1) = 1.57

Answer 5

after pi/2, the sin funciton falls... so you would see a negative slope in arcsin(sinx) as well

Answer 6

@rsadhvika is correct ! ;D

Answer 7

sin^-1(sint)=t, if -pi/2<t<pi/2
sin^-1(sinx)=x for -pi/2<x<pi/2