Question

How to solve for t:
0.5=0.7^(t/15).

I would appreciate it more if you help me how to do it, not give the exact answer right away :)

Answer 1

apply log

Answer 2

uhm, how? I'm very new

Answer 3

log .5 = t/15 log .7?

Answer 4

change of base

Answer 5

\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\]

Answer 6

t= 15 ln (0.5) / ln 0.7

Answer 7

yes

Answer 8

thanks kind sir

Answer 9

yw