Stats : In the population of adults the proportions of people in various marital status are : Single(Forever alone) =35%,Married =60%,Divourced =5% A person is selected at random.If that person is not divourced.Find the probability that he or she is singlle (i.e A/B) }
assume 100 people; how many people are single or married?
35 are single,60 are married and 5 are divourced.
and since we are only concerned with not divorced; that leaves us the set of single or married the total number of single or married is 95, correct? and how many of that set are single?
Okay yes 95 are married from which 35 are single.
|dw:1372683481260:dw| then 35 out of 95 gives a probablitity if 35/95
I don't undertand that diagram but 35/95 yeah..
the diagram is simply saying that: given the set B|dw:1372683811441:dw| the probability of A within B is just: the number of A within B, divided by the total number of B
so in this case: the set of not divorced consists of single + married the number of single within that set consists of single, therefore: \[P(single|(married~or~single))=\frac{single}{married+single}\]
Got it so,35/95 =0.3684210526
yep, which is usually rnded to 4 decies
So the end? The probablitity is 0.3684
thats the way i read it yes; some options love to put that into % format ... but its fine the way it is
Okay Thankyouuuu \(\Huge \color{magenta}{ \ddot \smile } \)
good luck ;)
:3
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