The average of 5 consecutive even numbers A,B,C,D and E is 52. What is the product of B and E?
implies that c=52 b is then 50 and e is 56 50*56?
answer plz
2800
x x+2 x+4 like that
\[ \frac{a + (a + 2) +(a + 4) + (a + 6) + 52 }{ 5 }\]
why c=52
since it is the average of consecutive terms, the middle term is just the average
for every question like that ya
next is a+8 la u put 52
oh im supposing x as c, not a
\[ \frac{a+(a+2)+(a+4)+(a+6)+52}{5} \] A = A B = (a + 2) C = (a +4) D = (a +6) E = (a + 8) = 52 E = 52 D = 44 = (a = 52 - 8) C = 38 = (a = 44 - 6) B = 34 = (a = 38 - 4) A = 32 = (a = 34 - 2) Product of B & E = 34 * 52 = 1768
wtf is thsi^
ohhh wait its the average of the 5 numbers is 52 or e is 52?
It could be both ways. lol anyways, she has the solution for both lol
If the average of a+b+c+d+e = 52 I would have worded it like The average of 5 consecutive even numbers A,B,C,D,E is 52 Anyways, it could be read both ways but the solution to both are here just in case anyone else looks it up and needs help
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