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Geometry 10 Online
OpenStudy (anonymous):

Help please! ASAP. Assume that the given statements are true. What conclusion, if any, can be drawn from these premises? ~p → q and r → ~q

OpenStudy (anonymous):

Any graph that goes with this out of curiosity?

OpenStudy (anonymous):

No, but can you please help me?

ganeshie8 (ganeshie8):

from the second conditional, we can write its contrapositive : q -> ~r

ganeshie8 (ganeshie8):

combining first conditional and this, ~p -> q and q -> ~r, you would get ~p-> ~r

OpenStudy (anonymous):

That's not an answer choice?

OpenStudy (anonymous):

Nevermind, I lied. It is! Thank you SO MUCH.

ganeshie8 (ganeshie8):

taking contrapositive again, you would get r->p

ganeshie8 (ganeshie8):

lol below two are same :- ~p->~r r -> p

OpenStudy (anonymous):

Wait so what's the answer?

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