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OpenStudy (lopezking1):
Solve for x.
6 over x equals x over 12
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OpenStudy (jack1):
6/x = x/12
\[\frac{ 6 }{ x } = \frac{ x }{ 12 }\]
so cross multiply to get x^2 = ...something
then solve for x
OpenStudy (lopezking1):
multiply both sides by 12.
OpenStudy (jack1):
yep,
and then multiply both sides by x
OpenStudy (jack1):
that way u get rid of the 2 denominators (12 and x)
OpenStudy (lopezking1):
which simplifies to 72
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OpenStudy (jack1):
on the LHS, yep
so what does the RHS equal...?
OpenStudy (lopezking1):
x
OpenStudy (jack1):
nope, x^2
\[x ^{2}\]
OpenStudy (lopezking1):
so then square 72
OpenStudy (jack1):
times both sides by 12
6/x * 12 = x/12 * 12
72 / x = x
then both sides by x
72 / x * x = x * x
72 = x^2
so x = sqrt 72
\[x = \sqrt{72}\]
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OpenStudy (jack1):
yep, and sqrt 72 =...?
OpenStudy (lopezking1):
\[6\sqrt{2}\]
OpenStudy (jack1):
cool, i woulda gone with 8.5 ish, but yours is way more exact ;)
understand it all tho dude?
OpenStudy (lopezking1):
Yeah thanks:D
OpenStudy (jack1):
no worries hey ;) best o luck
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