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Let cos p =.22. Which of the following is cos p/2
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half angle formula
\[\cos(\frac{x}{2})=\pm\sqrt{\frac{1+\cos(x)}{2}}\]
given an abc right triangle: \[cos(\frac{x}{2}) =\frac{ a}{\sqrt{2c(c-b)}}\]
oooh what is that?
thats just something a determined the other day :)
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where is the \(x\) in it? i mean which angle is it?
any angle
i cant figure it out. i suck at trig :(
in this case; a=sqrt(1-b^2)
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