Question

Given that f(3)=-1 and f'(3)=5, find an equation for the tangent line to the graph of y=f(x) at x=3

How do I do this?

Answer 1

use the point slope formula
\[y-y_1=m(x-x_1)\] with
\[x_1=3, y_1=-1, m=5\]

Answer 2

thanks