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OpenStudy (ja1):
x = 0, x = −2
x = 0, x = 2
x = 6, x = 2
x = 6, x = −2
OpenStudy (ja1):
I am brain dead on this one xD I forgot how to do these problems
OpenStudy (anonymous):
Is this supposed to be:
\[x^2=12x\]
OpenStudy (ja1):
Yupp
OpenStudy (ja1):
Wait no
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OpenStudy (anonymous):
\[6x^2=12x\]
OpenStudy (ja1):
\[6x^{2} = 12x\]
OpenStudy (ja1):
Yah lol
OpenStudy (anonymous):
Ok, start by dividing both sides by 6, so you get this:
\[x^2=2x\] Now subtract the 2x from both sides:
\[x^2 -2x=0\] From here we can factor out an x and we get:
\[x(x-2)=0\] After setting both factors equal to 0 we find x=0 or x=2
OpenStudy (ja1):
Yes but how do you get 2 solutions that's were I am stuck :/
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OpenStudy (anonymous):
Once you have the two factors, you set each factor equal to 0. So, we set x=0 and x-2=0. Solving for x on the second one gives us x=2. Try plugging both solutions into the original to check them.
OpenStudy (ja1):
OHHH ok I understand now
OpenStudy (ja1):
I went kinda blank on this one
OpenStudy (ja1):
Thanks :D
OpenStudy (anonymous):
That happens sometimes. Glad I could help.
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