Question

For y = x2 + 6x − 16,

Determine if the parabola opens up or down.
State if the vertex will be a maximum or minimum.
Find the vertex.
Find the x-intercepts.
Describe the graph of the equation.
Show all work and use complete sentences

Answer 1

Given ax²+bx+c
Parabola Direction: Up if a is positive, down if a is negative.
Vertex: Maximum if a is negative, minimum if a is positive
Vertex: x = (-b/2a). Plug that into the function to find the y value
x intercepts: y=0. Solve this however you like, quadratic formula etc.