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Graph the function, with the focus and directrix shown on the graph, as well. Attachment
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@julian25
ok lets consider firts this function x= (1/8)y^2 we would find te focus and after that we will translate it to find the focus of this x-2 = (1/8)(y+1)^2
ok
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first we must take that equation into this form y^2 = 4px where p is the focus
so we have 4*2*x= y^2
could u find the focus from therE?
the focus would be 0,2
no really |dw:1372755500109:dw|
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