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Mathematics 9 Online
OpenStudy (anonymous):

Speed time graph question

OpenStudy (anonymous):

I got the answers i just want someone to confirm that i am correct? T=0.3794733192 and V= 1.897366596\

OpenStudy (cwrw238):

total distance = area under the graph so 1.44 = 0.5VT + 0.5VT + VT = 2VT and acceleration = V/T = 5 agreed?

OpenStudy (anonymous):

cool @cwrw238

OpenStudy (cwrw238):

no, one mistake the area is in km and acceleration is in m/ s^2 so correct is 1440 = 2VT

OpenStudy (cwrw238):

so you need to solve the 2 equations VT = 720 V = 720/T substituting 5 = 720 / T^2 T^2 = 720 / 5 = 144 T = 12

OpenStudy (cwrw238):

find V by plugging T= 12 into 1440 = VT

OpenStudy (cwrw238):

V is in m/s and T is in seconds

OpenStudy (anonymous):

t=19.25 n speed =40

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