Question

Graph the function, with the focus and directrix shown on the graph, as well. Attachment

Answer 1

@julian25

Answer 2

we must consider this first
y= -(1/16)x^2

Answer 3

could u get that into the form
x^2 = 4*p*y

Answer 4

are you asking for focus

Answer 5

yes

Answer 6

0,4

Answer 7

close

Answer 8

0,2

Answer 9

take this equation
y= -(1/16)x^2

Answer 10

and transfor it into this form
x^2 = 4*p*y

Answer 11

so u can find the value of p

Answer 12

-4?

Answer 13

yes

Answer 14

that is the x or the y value?

Answer 15

x value

Answer 16

it is not
u must see the file that i have atacched

Answer 17

oooo 0,-4

Answer 18

yes

Answer 19

directrix is 4

Answer 20

y=4
yes

Answer 21

now we must translate it
to find the focus of
(y-2)=(-1/16)(x-1)^2

Answer 22

ok

Answer 23

x-1 meanst translate it 1 unit to the right

Answer 24

so -3

Answer 25

the x coordinate was x=0

Answer 26

translate it 1 unit to the right

Answer 27

o right so its 1

Answer 28

x=1

Answer 29

now y-2 mean translate it 2 units upward

Answer 30

x = 2

Answer 31

we r working with the y coordinate

Answer 32

oh so y = 2

Answer 33

this is what u wrote
oooo 0,-4

Answer 34

the y coordinate there is y=-4
translate it 2 units upward

Answer 35

I did! is it y = -2

Answer 36

x=1, y=-2
that is the focus

Answer 37

ok

Answer 38

directrix is ?

Answer 39

2

Answer 40

y=2

Answer 41

the directrix was a horizontal line
y=4
translate it 2 units upward

Answer 42

y = 6

Answer 43

yes

Answer 44

which way does the loop go? @julian25

Answer 45

u meant the shape of the graph?

Answer 46

No the parabola

Answer 47

up or down

Answer 48

so