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How would i set up the equation to solve this problem?
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given crossing secants, the ratio of parts is equal
|dw:1372777596824:dw|
the crossing is outside the cirlce on yours, but the parts are still there
So, 53x= 62x ?
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|dw:1372777703189:dw|
i still dont get how to set up the equation..your problem doesnt look like mine.
thats spose to be a 5 up top, not a 3x lol
ohh.. 5x+5+3x=6+6+2x ??
|dw:1372777782278:dw|
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since there are parts that need to be added: 6 + 2x and 5 + 3x to make a total length of one part of the crossings
so: 5(5+3x) = 6(6+2x)
..k
x=11/3
25+15x = 36+12x 3x = 11 yes so, since JK is 3x, JK = 3(11/3)
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thx.(:
yw
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