Solve the problem. During the 1998-1999 Junior Hockey League season, the Sharks played 54 games. Together, their wins and loses totaled 46. They tied 5 fewer games than they lost. How many games did they win that season?

A. 8 games

B. 33 games

C. 13 games

D. 29 games

Question

Solve the problem. During the 1998-1999 Junior Hockey League season, the Sharks played 54 games. Together, their wins and loses totaled 46. They tied 5 fewer games than they lost. How many games did they win that season?

A. 8 games	

B. 33 games	

C. 13 games	

D. 29 games

anonymous · Answer

Lets set up some variables
w +l = 46
t = l-5
w+l+t = 54

anonymous · Answer

by interchanging the first equation into the last one - you should be able to determine value of T

anonymous · Answer

from that - determine value of L with 2nd equation 
and last, determine W value with 1st equation.

Please tell me what you got for T L and W

anonymous · Answer

is it 46?

whpalmer4 · Answer

Let W be the number of games won, L be the number lost, and T be the number tied.

They played 54 games, so W + L + T = 54.
The count of wins and losses was 46, so W+L = 46.  This means we can write
W+L+T = 54
(W+L) + T = 54
46 + T = 54
T = 8
They tied 5 few games than they lost: T+5 = L
8+5 = L = 13
W+L = 46
W+13 = 46
W = ?