Question

What is the 6th term of the geometric sequence where a1 = 625 and a3 = 25?

0.0016

0.008

0.04

0.2

Answer 1

It is 0.2
you divide by 5 to get the next term
625/5=125
125/5=25
25/5=5
5/5=1
1/5=.2

Answer 2

nth term = a r ^ ( n - 1 )
3rd term = 25 = 625 r ^ ( 3 - 1 )
25 = 625 r ²
r^2 = 25 / 625
r = 5 / 25
r= 1 / 5

6th term = 625 ( 1 / 5 ) ^ ( 6 - 1 )
= 625 ( 1 / 5 ) ^5
= 625 ( 1 / 3,125 )
= 1 / 5
= 0.2

Answer 3

Thank you!

Answer 4

My Pleasure.