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Physics 9 Online
OpenStudy (anonymous):

Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum? A. 13 seconds B. 1.3 seconds C. 3.5 seconds D. 0.76 seconds

OpenStudy (souvik):

\[T=2\pi \sqrt{L/g}\]

OpenStudy (theeric):

That link backs up souvik's response. It might also help you find other information.

OpenStudy (anonymous):

Thank you both :) @theEric that link was very helpful Grazie

OpenStudy (theeric):

You're welcome! And I guess that equation only works for a "simple pendulum."

OpenStudy (souvik):

any problem? @SNIIX18

OpenStudy (anonymous):

yahh i cant wrap my finger around this problem its kind of difficult

OpenStudy (souvik):

this question?

OpenStudy (anonymous):

yes it's kind of difficult for me

OpenStudy (souvik):

what happened?

OpenStudy (anonymous):

i just dont understand

OpenStudy (souvik):

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