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Physics
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OpenStudy (anonymous):
Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum?
A. 13 seconds
B. 1.3 seconds
C. 3.5 seconds
D. 0.76 seconds
12 years ago
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OpenStudy (souvik):
\[T=2\pi \sqrt{L/g}\]
12 years ago
OpenStudy (theeric):
That link backs up souvik's response. It might also help you find other information.
12 years ago
OpenStudy (anonymous):
Thank you both :) @theEric that link was very helpful Grazie
12 years ago
OpenStudy (theeric):
You're welcome! And I guess that equation only works for a "simple pendulum."
12 years ago
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OpenStudy (souvik):
any problem? @SNIIX18
12 years ago
OpenStudy (anonymous):
yahh i cant wrap my finger around this problem its kind of difficult
12 years ago
OpenStudy (souvik):
this question?
12 years ago
OpenStudy (anonymous):
yes it's kind of difficult for me
12 years ago
OpenStudy (souvik):
what happened?
12 years ago
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OpenStudy (anonymous):
i just dont understand
12 years ago
OpenStudy (souvik):
|dw:1372793064271:dw|
12 years ago
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