4x2 + 9y2 = 72 x - y2 = -1 Select all of the following that are solutions to the system shown. (3, 2) (3, -2) (-3, 2) (-3, -2)
Ok, I would use substitution for this one. Do you know how to start that?
so you have the "x" and the "y" terms squared if they're both POSITIVE, is an ellipse, or a circle which is really just a "round ellipse" if they're both NEGATIVE, is a hyperbola they're both POSITIVE, thus is an ellipse
well, I take that back, IF ONLY ONE OF THEM IS NEGATIVE, then is a hyperbola :)
i got (3, 2) and (3, -2)...is that right??
ohh, wait.. is a system of equations, my bad heheh
thought they were asking for the center pfft
x - y2 = -1 -y2=-x - 1 y^2= x+1
(3, 2) 4=4 good (3, -2) 4=4 good (-3, 2) 4=-2 no (-3, -2) 4=-2 no a and b
thank you (:
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