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how to solve log4^16
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4 is the base right?
yes
how would you write 16 as a power of 4?
oh
ie what is x in 4^x = 16
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4^2
2
so log(4, 16) = log(4, 4^2) log(4, 16) = 2*log(4, 4) log(4, 16) = 2*1 log(4, 16) = 2
or you can use the change of base formula to get log(4, 16) = log(16)/log(4) log(4, 16) = 2
ok thnaks i got it
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