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4(x-4)^2-1 have to graph this
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this is a quadratic equation in vertex form. It follows the format \[\large a(x-h)^2+k\]
Your equation \(\large 4(x-\color{green}4)^2 +\color{red}{(-1)}\) had the vertex (4,-1).
thank you
the \(\large a\) or \(4\) in your equation tells you whether the parabola opens up or down depending on the value of the sign. In this case, the value is positive, therefore your parabola opens upwards.
Are you good to go or do you need more help in understanding how to graph? :)
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