Andrea's change purse contained 8 quarters, 9 dimes, and 8 nickels.If andrea chose 2 coins randomly without replacing them in her purse,what is the probability that she chose 2 dimes?
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OpenStudy (anonymous):
flutter you
OpenStudy (anonymous):
uhm, excuse me. but can i get an explanation on this problem,please really stuck on this.
OpenStudy (swissgirl):
ok so we have 25 coins altogether
OpenStudy (swissgirl):
and we have 9 dimes
OpenStudy (anonymous):
okay im following
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OpenStudy (swissgirl):
So the first time we choose a coin the probability that it will be a dime is 9/25 correct?
OpenStudy (anonymous):
Yeah?
OpenStudy (swissgirl):
ya there are 25 coins altogether and 9 dimes so the probability that it will be a dime is dimes/total amt of coins = 9/25
OpenStudy (swissgirl):
The second time we choose a coin
OpenStudy (anonymous):
okay i get you
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OpenStudy (swissgirl):
there are only 24 coins left cuz we picked a dime
OpenStudy (anonymous):
okay
OpenStudy (swissgirl):
so there are 24 coins and 8 dimes so the probabiity we will choose a dime is 8/24
OpenStudy (swissgirl):
So altogether the probability that we will choose 2 dimes is 9/25*8/24
OpenStudy (anonymous):
so the answer would be 3/25, right?
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