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OpenStudy (anonymous):
let f(x)=1/x, g(x)=x^2-2x Find g(f(2))... I am working this problem and first i had it now i think i'm doing something wrong... my solution was -2 1/4... is this right??
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OpenStudy (zzr0ck3r):
what is f(2)?
OpenStudy (anonymous):
g(x)=x^2-2x Plug in 1/2 for x
OpenStudy (souvik):
(1/2)^2-2(1/2)=?
OpenStudy (anonymous):
-3/4
OpenStudy (souvik):
right...
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OpenStudy (anonymous):
thx
OpenStudy (anonymous):
thanks to you too futuremathprofessor
OpenStudy (anonymous):
Anytime :)
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